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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 26 June 2022, Shift 1, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

An expression for a dimensionless quantity P is given by P=αβlog⁡e(ktβx)P=\frac{\alpha}{\beta}\log_e\left(\frac{kt}{\beta x}\right); where α\alpha and β\beta are constants, xx is distance; k is Boltzmann constant and t is the temperature. Then the dimensions of α\alpha will be :
  1. (1)[M0 L−1 T0][\mathrm{M^0\,L^{-1}\,T^0}]
  2. (2)[M L0 T−2][\mathrm{M\,L^0\,T^{-2}}]
  3. (3)[M L T−2][\mathrm{M\,L\,T^{-2}}]Official answer
  4. (4)[M L2 T−2][\mathrm{M\,L^2\,T^{-2}}]

Official answer

Option 3

NTA final key.

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.