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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 25 June 2022, Shift 2, Chemistry Q61

Question 61 of 90 in this shift, Chemistry question 1 of 30, Section A.

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1.3×1015 s−11.3 \times 10^{15}\ \mathrm{s^{-1}} and h=6.6×10−34 J s\mathrm{h} = 6.6 \times 10^{-34}\ \mathrm{J\ s}.]
  1. (1)3.21×10−14 J3.21 \times 10^{-14}\ \mathrm{J}
  2. (2)6.24×10−16 J6.24 \times 10^{-16}\ \mathrm{J}
  3. (3)8.58×10−19 J8.58 \times 10^{-19}\ \mathrm{J}Official answer
  4. (4)9.76×10−20 J9.76 \times 10^{-20}\ \mathrm{J}

Official answer

Option 3

NTA final key.

Chapter
Structure of Atom
Topic
Photoelectric Effect
Idea tested
Work Function and Threshold

Same idea in other shifts

Asked 10× in all
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  7. 26 Jun 2022, Shift 2 · Q60The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 6630 Å is 0.42 V. If the threshold…MediumNumerical value
  8. 28 Jun 2022, Shift 1 · Q82If the work function of a metal is 6.63×10−196.63 \times 10^{-19}J, the maximum wavelength of the photon required to remove a photoelectron from…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.