The number of N atoms in 681 g of $\mathrm{C_7H_5N_3O_6}$ is $x \times 10^{21}$. The value of $x$ is __________. ($\mathrm{N_A} = 6.02 \times 10^{23}\ \mathrm{mol^{-1}}$) (Nearest Integer)

JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 25 June 2022, Shift 1, Chemistry Q81

Question 81 of 90 in this shift, Chemistry question 21 of 30, Section B.

The number of N atoms in 681 g of

\mathrm{C_7H_5N_3O_6}

x \times 10^{21}

. The value of

x

is __________. (

\mathrm{N_A} = 6.02 \times 10^{23}\ \mathrm{mol^{-1}}

) (Nearest Integer)

Official answer

5418

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Mole and Avogadro Calculations

Same idea in other shifts

Asked 11× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.