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Saturday, 31 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 25 June 2022, Shift 1, Maths Q25

Question 25 of 90 in this shift, Maths question 25 of 30, Section B.

The number of values of xx in the interval (π4,7π4)\left(\frac{\pi}{4},\frac{7\pi}{4}\right) for which 14cosec2x−2sin⁡2x=21−4cos⁡2x14\mathrm{cosec}^2x-2\sin^2x=21-4\cos^2x holds, is __________.

Official answer

4

NTA final key.

Same topic in other shifts

All General Solutions questions
  1. 2 Apr 2026, Shift 1 · Q12Let S={x∈[−π,π]:sin⁡x(sin⁡x+cos⁡x)=a,a∈Z}S=\{x \in [-\pi, \pi] : \sin x(\sin x+\cos x)=a, a \in \mathbb{Z}\}. Then n(S)n(S) is equal to :HardSingle correct
  2. 5 Apr 2026, Shift 2 · Q23If S={θ∈[−π,π]:cos⁡θcos⁡5θ2=cos⁡7θcos⁡7θ2}S=\left\{\theta \in [-\pi, \pi] : \cos\theta\cos\frac{5\theta}{2}=\cos 7\theta\cos\frac{7\theta}{2}\right\}, then n(S) is equal to…HardNumerical value
  3. 6 Apr 2026, Shift 1 · Q14Let S={θ∈(−2π,2π):cos⁡θ+1=3sin⁡θ}\mathrm{S}=\left\{\theta\in(-2\pi,2\pi):\cos\theta+1=\sqrt{3}\sin\theta\right\}. Then ∑θ∈Sθ\sum_{\theta\in \mathrm{S}}\theta is equal to:MediumSingle correct
  4. 2 Apr 2025, Shift 1 · Q3If θ∈[−2π,2π]\theta\in[-2\pi, 2\pi], then the number of solutions of 22cos⁡2θ+(2−6)cos⁡θ−3=02\sqrt{2}\cos^2\theta+(2-\sqrt{6})\cos\theta-\sqrt{3}=0, is equal to :MediumSingle correct
  5. 2 Apr 2025, Shift 2 · Q13If θ∈[−7π6,4π3]\theta \in \left[-\frac{7\pi}{6}, \frac{4\pi}{3}\right], then the number of solutions of…MediumSingle correct
  6. 3 Apr 2025, Shift 1 · Q10The number of solutions of the equation 2x+3tan⁡x=π2x + 3\tan x = \pi, x∈[−2π,2π]−{±π2,±3π2}x \in [-2\pi, 2\pi] - \left\{\pm\frac{\pi}{2}, \pm\frac{3\pi}{2}\right\} is:MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.