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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 24 June 2022, Shift 2, Chemistry Q76

Question 76 of 90 in this shift, Chemistry question 16 of 30, Section A.

Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is
  1. (1)2-pentene
  2. (2)propanaldehyde
  3. (3)2-buteneOfficial answer
  4. (4)4-methylpent-2-ene

Official answer

Option 3

NTA final key.

Chapter
Aldehydes, Ketones and Carboxylic Acids
Topic
Carboxylic Acids and Derivatives
Idea tested
Decarboxylation Reactions

Same idea in other shifts

Asked 2× in all
  1. 4 Sep 2020, Shift 1 · Q43[P] on treatment with Br2/FeBr3\mathrm{Br_2/FeBr_3} in CCl4\mathrm{CCl_4} produced a single isomer C8H7O2Br\mathrm{C_8H_7O_2Br} while heating [P] with…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.