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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 24 June 2022, Shift 2, Physics Q47

Question 47 of 90 in this shift, Physics question 17 of 30, Section A.

An electric bulb is rated as 200 W. What will be the peak magnetic field at 4 m distance produced by the radiations coming from this bulb? Consider this bulb as a point source with 3.5% efficiency.
  1. (1)1.19×10−8T1.19 \times 10^{-8}T
  2. (2)1.71×10−8T1.71 \times 10^{-8}TOfficial answer
  3. (3)0.84×10−8T0.84 \times 10^{-8}T
  4. (4)3.36×10−8T3.36 \times 10^{-8}T

Official answer

Option 2

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.