JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 30 July 2022, Shift 2, Chemistry Q54

Question 54 of 90 in this shift, Chemistry question 24 of 30, Section B.

50 mL of 0.1 M

\mathrm{CH_3COOH}

is titrated against 0.1 M NaOH solution. When 10 mL of NaOH is added, the pH of the solution becomes ________

\times 10^{-1}

. (nearest integer) Given: pKa (

\mathrm{CH_3COOH}

) = 4.8, log 2 = 0.3

Official answer

NTA final key.

Chapter: Equilibrium
Topic: pH and Buffers
Idea tested: Acidic Buffer pH Calculation

Same idea in other shifts

Asked 4× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.