JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation
JEE Main 30 July 2022, Shift 2, Physics Q19
Question 19 of 90 in this shift, Physics question 19 of 30, Section A.
The de Broglie wavelength associated with an electron, accelerated through a potential difference of 15056 V, is:
- (1)0.1 ÅOfficial answer
- (2)1 Å
- (3)10 Å
- (4)100 Å
Official answer
Option 1
NTA final key.
- Topic
- Matter Waves
- Idea tested
- Wavelength from Accelerating Potential