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Saturday, 31 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 29 July 2022, Shift 1, Maths Q28

Question 28 of 90 in this shift, Maths question 28 of 30, Section B.

If 12×3×4+13×4×5+14×5×6+…+1100×101×102=k101\frac{1}{2 \times 3 \times 4} + \frac{1}{3 \times 4 \times 5} + \frac{1}{4 \times 5 \times 6} + \ldots + \frac{1}{100 \times 101 \times 102} = \frac{k}{101}, then 34k34k is equal to __________.

Official answer

286

NTA final key.