JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyApplication
JEE Main 28 July 2022, Shift 2, Physics Q9
Question 9 of 90 in this shift, Physics question 9 of 30, Section A.
A slab of dielectric constant K has the same cross-sectional area as the plates of a parallel plate capacitor and thickness d, where d is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be :
(Given = capacitance of capacitor with air as medium between plates.)
- (1)Official answer
- (2)
- (3)
- (4)
Official answer
Option 1
NTA final key.
- Topic
- Dielectrics
- Idea tested
- Partial and Multiple Slabs