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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 27 July 2022, Shift 2, Chemistry Q82

Question 82 of 90 in this shift, Chemistry question 22 of 30, Section B.

For a real gas at 25°C temperature and high pressure (99 bar) the value of compressibility factor is 2, so the value of Vander Waal’s constant ‘b’ should be __________ ×10−2\times10^{-2} L mol−1\mathrm{mol^{-1}} (Nearest integer) (Given R=0.083 L bar K−1mol−1\mathrm{R=0.083\ L\ bar\ K^{-1}mol^{-1}})

Official answer

25

NTA final key.

Chapter
States of Matter
Topic
Real Gases
Idea tested
Compressibility Factor Z

Same idea in other shifts

Asked 2× in all
  1. 13 Apr 2023, Shift 1 · Q82A certain quantity of real gas occupies a volume of 0.15 dm30.15\ \mathrm{dm^3} at 100 atm and 500 K when its compressibility factor is 1.07.…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.