JEE Main 2022 · ChemistryMultiple choiceSingle correctEasyApplication

JEE Main 27 July 2022, Shift 2, Chemistry Q61

Question 61 of 90 in this shift, Chemistry question 1 of 30, Section A.

The correct decreasing order of energy for the orbitals having, following set of quantum numbers : (A)

n=3

l=0

m=0

(B)

n=4

l=0

m=0

(C)

n=3

l=1

m=0

(D)

n=3

l=2

m=1

is :

(1)(D) > (B) > (C) > (A)Official answer
(2)(B) > (D) > (C) > (A)
(3)(C) > (B) > (D) > (A)
(4)(B) > (C) > (D) > (A)

Official answer

Option 1

NTA final key.

Chapter: Structure of Atom
Topic: Quantum Numbers
Idea tested: Aufbau Principle and n+l Rule

Same idea in other shifts

Asked 8× in all

4 Apr 2026, Shift 1 · Q53Which of the following is correct set of $4$ quantum numbers of $19^{\text{th}}$ electron in Chromium (Atomic number $=24$ ) in accordance…MediumSingle correct
5 Apr 2026, Shift 1 · Q52Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. A. $n = 3, l = 2, m = +1$ B.…MediumOther
5 Apr 2026, Shift 2 · Q52Which of the following statement(s) is/are true ? A. If two orbitals have the same value of $(n+l)$ , the orbital with lower value of n…MediumOther
9 Apr 2024, Shift 1 · Q61Compare the energies of following sets of quantum numbers for multielectron system. (A) $n=4, l=1$ (B) $n=4, l=2$ (C) $n=3, l=1$ (D)…EasySingle correct
29 Jul 2022, Shift 2 · Q62Given below are the quantum numbers for 4 electrons. A. $n = 3, l = 2, m_l = 1, m_s = +1/2$ B. $n = 4, l = 1, m_l = 0, m_s = +1/2$ C.…MediumSingle correct
22 Jul 2021, Shift 2 · Q53Number of electrons that Vanadium (Z=23) has in p-orbitals is equal to ________.EasyNumerical value
5 Sep 2020, Shift 1 · Q33In the sixth period, the orbitals that are filled are :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.