JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 27 July 2022, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

A compass needle of oscillation magnetometer oscillates 20 times per minute at a place P of dip

30^\circ

. The number of oscillations per minute become 10 at another place Q of

60^\circ

dip. The ratio of the total magnetic field at the two places (

\mathrm{B_Q : B_P}

) is :

(1) $\sqrt{3}:4$ Official answer
(2) $4:\sqrt{3}$
(3) $\sqrt{3}:2$
(4) $2:\sqrt{3}$

Official answer

Option 1

NTA final key.

Chapter: Magnetism and Matter
Topic: Earth's Magnetism
Idea tested: Vibration Magnetometer Time Period

Same topic in other shifts

All Earth's Magnetism questions

12 Apr 2023, Shift 1 · Q51A compass needle oscillates 20 times per minute at a place where the dip is $30^\circ$ and 30 times per minute where the dip is…HardNumerical value
27 Jul 2022, Shift 1 · Q43A magnet hung at 45° with magnetic meridian makes an angle of 60° with the horizontal. The actual value of the angle of dip is -MediumSingle correct
29 Jul 2022, Shift 2 · Q48The vertical component of the earth's magnetic field is $6\times10^{-5}$ T at any place where the angle of dip is $37^\circ$ . The earth's…EasySingle correct
29 Jun 2022, Shift 1 · Q45At a certain place the angle of dip is $30^\circ$ and the horizontal component of earth's magnetic field is 0.5 G. The earth's total…EasySingle correct
22 Jul 2021, Shift 2 · Q2Choose the correct option :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.