[figure: benzene ring (hexagon with inner circle) with CH2OH at the top and OH at the bottom (para)] $+$ HCl $\xrightarrow{\Delta}$ A $\xrightarrow{\text{NaI}}$ B In the above reaction product B is: Product B is

Option 1: [figure: benzene ring with CH2I at top and OH at bottom (para)]

[figure: benzene ring with CH2I at top and OH at bottom (para)]

[figure: benzene ring with CH2I at top and I at bottom (para)]

[figure: benzene ring with CH2Cl at top and OH at bottom (para)]

[figure: benzene ring with CH2Cl at top and I at bottom (para)]

JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumMulti-step

JEE Main 27 July 2022, Shift 1, Chemistry Q75

Question 75 of 90 in this shift, Chemistry question 15 of 30, Section A.

[figure: benzene ring (hexagon with inner circle) with CH2OH at the top and OH at the bottom (para)]

+

HCl

\xrightarrow{\Delta}

\xrightarrow{\text{NaI}}

B In the above reaction product B is: Product B is

The figure, in words

Reactant drawn as benzene ring (hexagon with inner circle) bearing CH2OH at the top and OH at the bottom, plus HCl, arrow with delta over it to A, then arrow labelled NaI to B. Each option is a para-disubstituted benzene ring drawn the same way.

(1)[figure: benzene ring with CH2I at top and OH at bottom (para)]Official answer
(2)[figure: benzene ring with CH2I at top and I at bottom (para)]
(3)[figure: benzene ring with CH2Cl at top and OH at bottom (para)]
(4)[figure: benzene ring with CH2Cl at top and I at bottom (para)]

Official answer

Option 1

NTA final key.

Chapter: Alcohols, Phenols and Ethers
Topic: SN1 and SN2 Mechanisms
Idea tested: Finkelstein Reaction

JEE Main 27 July 2022, Shift 1, Chemistry Q75

Same idea in other shifts