JEE Main 2022 (27 Jul, Shift 1) Physics Q47: Matter Waves

Question

An electron (mass m) with an initial velocity $\vec{v}=v_0\hat{i}$ ($v_0>0$) is moving in an electric field $\vec{E}=-E_0\hat{i}$ ($E_0>0$) where $E_0$ is constant. If at t=0 de Broglie wavelength is $\lambda_0=\frac{h}{mv_0}$ ,then its de Broglie wavelength after time t is given by

Accepted Answer

Option 4: $\frac{\lambda_0}{\left(1+\frac{eE_0t}{mv_0}\right)}$

Answer

$\lambda_0$

Answer

$\lambda_0\left(1+\frac{eE_0t}{mv_0}\right)$

Answer

$\lambda_0 t$

Answer

$\frac{\lambda_0}{\left(1+\frac{eE_0t}{mv_0}\right)}$

JEE Main 27 July 2022, Shift 1, Physics Q47

Same idea in other shifts