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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 2, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10−6 sin⁡1000π(5x−4×108t)T.B_y = 5 \times 10^{-6}\ \sin 1000\pi(5x - 4 \times 10^{8}t)T. The amplitude of electric field will be :
  1. (1)15×102 Vm−115 \times 10^{2}\ Vm^{-1}
  2. (2)5×10−6 Vm−15 \times 10^{-6}\ Vm^{-1}
  3. (3)16×1012 Vm−116 \times 10^{12}\ Vm^{-1}
  4. (4)4×102 Vm−14 \times 10^{2}\ Vm^{-1}Official answer

Official answer

Option 4

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.