JEE Main 2022 (26 Jul, Shift 1) Chemistry Q76: Amines

Question

The major product of the following reaction is
[figure: benzene ring with $\mathrm{OCH_3}$ on the top vertex and $\mathrm{O_2N}$ on the adjacent upper-left vertex] $\xrightarrow[	ext{(ii) } \mathrm{CH_3CH_2OH}]{	ext{(i) Na/liq.}\mathrm{NH_3}}$

Accepted Answer

Option 1: [figure: six-membered ring; one ring carbon bears H and $\mathrm{O_2N}$ (sp3), the adjacent ring carbon bears $\mathrm{OCH_3}$; two C=C double bonds drawn in the ring (one on the $\mathrm{OCH_3}$-bearing carbon, one along the lower-left edge)]

Answer

[figure: six-membered ring; one ring carbon bears H and $\mathrm{O_2N}$ (sp3), the adjacent ring carbon bears $\mathrm{OCH_3}$; two C=C double bonds drawn in the ring (one on the $\mathrm{OCH_3}$-bearing carbon, one along the lower-left edge)]

Answer

[figure: six-membered ring; one ring carbon bears H and $\mathrm{H_2N}$ (sp3), the adjacent ring carbon bears $\mathrm{OCH_3}$; two C=C double bonds drawn in the ring (one on the $\mathrm{OCH_3}$-bearing carbon, one along the lower-left edge)]

Answer

[figure: six-membered ring; top ring carbon bears OH, the adjacent left ring carbon bears $\mathrm{O_2N}$; C=C double bond between these two carbons and a second C=C along the lower-right edge]

Answer

[figure: six-membered ring; top ring carbon bears $\mathrm{OCH_3}$ and H (sp3), the adjacent left ring carbon bears $\mathrm{O_2N}$; two C=C double bonds drawn along the left and right sides of the ring]

JEE Main 26 July 2022, Shift 1, Chemistry Q76

Same topic in other shifts