JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 25 July 2022, Shift 2, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength

\lambda

. The value of principal quantum number 'n' of the excited state will be : (R : Rydberg constant)

(1) $\sqrt{\frac{\lambda R}{\lambda - 1}}$
(2) $\sqrt{\frac{\lambda R}{\lambda R - 1}}$ Official answer
(3) $\sqrt{\frac{\lambda}{\lambda R - 1}}$
(4) $\sqrt{\frac{\lambda R^{2}}{\lambda R - 1}}$

Official answer

Option 2

NTA final key.

Chapter: Atoms
Topic: Bohr's Atomic Model
Idea tested: Rydberg Formula and Spectra

Same idea in other shifts

Asked 10× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.