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Saturday, 31 October

JEE Main 2022 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 25 July 2022, Shift 2, Maths Q29

Question 29 of 90 in this shift, Maths question 29 of 30, Section B.

Let the area enclosed by the xx-axis, and the tangent and normal drawn to the curve 4x3−3xy2+6x2−5xy−8y2+9x+14=04x^3-3xy^2+6x^2-5xy-8y^2+9x+14=0 at the point (−2,3)(-2,3) be AA. Then 8A8A is equal to ___________.

Official answer

170

NTA final key.

Same topic in other shifts

All Tangents and Normals questions
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  6. 27 Jul 2022, Shift 2 · Q29A common tangent T to the curves C1:x24+y29=1C_1 : \frac{x^2}{4} + \frac{y^2}{9} = 1 and C2:x242−y2143=1C_2 : \frac{x^2}{42} - \frac{y^2}{143} = 1 does not pass…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.