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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 25 July 2022, Shift 1, Maths Q14

Question 14 of 90 in this shift, Maths question 14 of 30, Section A.

Let PP be the plane containing the straight line x−39=y+4−1=z−7−5\frac{x-3}{9}=\frac{y+4}{-1}=\frac{z-7}{-5} and perpendicular to the plane containing the straight lines x2=y3=z5\frac{x}{2}=\frac{y}{3}=\frac{z}{5} and x3=y7=z8\frac{x}{3}=\frac{y}{7}=\frac{z}{8}. If dd is the distance of PP from the point (2,−5,11)(2,-5,11), then d2d^2 is equal to :
  1. (1)1472\frac{147}{2}
  2. (2)9696
  3. (3)323\frac{32}{3}Official answer
  4. (4)5454

Official answer

Option 3

NTA final key (2022 Session 2).