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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 18 March 2021, Shift 2, Maths Q69

Question 69 of 90 in this shift, Maths question 9 of 30, Section A.

Let y=y(x)y=y(x) be the solution of the differential equation dydx=(y+1)((y+1)ex2/2−x)\frac{dy}{dx}=(y+1)\left((y+1)e^{x^2/2}-x\right), 0<x<2.10<x<2.1, with y(2)=0y(2)=0. Then the value of dydx\frac{dy}{dx} at x=1x=1 is equal to :
  1. (1)e5/2(1+e2)2\frac{e^{5/2}}{(1+e^2)^2}
  2. (2)−2e2(1+e2)2-\frac{2e^2}{(1+e^2)^2}
  3. (3)5e1/2(e2+1)2\frac{5e^{1/2}}{(e^2+1)^2}
  4. (4)−e3/2(e2+1)2\frac{-e^{3/2}}{(e^2+1)^2}Official answer

Official answer

Option 4

NTA final key.