JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 17 March 2021, Shift 2, Physics Q24

Question 24 of 90 in this shift, Physics question 24 of 30, Section B.

The electric field intensity produced by the radiation coming from a 100 W bulb at a distance of 3 m is E. The electric field intensity produced by the radiation coming from 60 W at the same distance is

\sqrt{\frac{x}{5}}

E. Where the value of

x=

____________.

Official answer

NTA final key.

Chapter: Electromagnetic Waves
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy