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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedHardCalculation

JEE Main 17 March 2021, Shift 2, Physics Q16

Question 16 of 90 in this shift, Physics question 16 of 30, Section A.

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of 15 Ω\Omega resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of 10 V is maintained across AC.

The figure, in words

Wheatstone bridge drawn as a diamond with corners A (left), B (top), C (right), D (bottom): AB = 100 ohm, BC = 10 ohm, AD = 60 ohm, DC = 5 ohm; a galvanometer G (circle with an arrow) connects B and D vertically; a 10 V cell is connected between A and C through an external wire loop below the bridge.
  1. (1)2.44 μA2.44\ \mu\mathrm{A}
  2. (2)2.44 mA2.44\ \mathrm{mA}
  3. (3)4.87 μA4.87\ \mu\mathrm{A}
  4. (4)4.87 mA4.87\ \mathrm{mA}Official answer

Official answer

Option 4

NTA final key.