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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 17 March 2021, Shift 2, Physics Q10

Question 10 of 90 in this shift, Physics question 10 of 30, Section A.

A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to 81100\frac{81}{100} of the height through which it falls. Find the average speed of the ball. (Take g=10 ms−2g=10\ \mathrm{ms^{-2}})
  1. (1)2.0 ms−12.0\ \mathrm{ms^{-1}}
  2. (2)2.50 ms−12.50\ \mathrm{ms^{-1}}Official answer
  3. (3)3.0 ms−13.0\ \mathrm{ms^{-1}}
  4. (4)3.50 ms−13.50\ \mathrm{ms^{-1}}

Official answer

Option 2

NTA final key.

Chapter
Motion in a Straight Line
Topic
Collisions
Idea tested
Total Distance for Bouncing Ball

Same topic in other shifts

All Collisions questions
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  5. 9 Apr 2024, Shift 2 · Q33A nucleus at rest disintegrates into two smaller nuclei with their masses in the ratio of 2:12:1. After disintegration they will move :EasySingle correct
  6. 1 Feb 2024, Shift 1 · Q35A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10−210^{-2} kg moving with a speed of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.