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Saturday, 31 October

JEE Main 2021 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 17 March 2021, Shift 1, Maths Q90

Question 90 of 90 in this shift, Maths question 30 of 30, Section B.

If a⃗=αi^+βj^+3k^\vec{a}=\alpha\hat{i}+\beta\hat{j}+3\hat{k}, b⃗=−βi^−αj^−k^\vec{b}=-\beta\hat{i}-\alpha\hat{j}-\hat{k} and c⃗=i^−2j^−k^\vec{c}=\hat{i}-2\hat{j}-\hat{k} such that a⃗⋅b⃗=1\vec{a}\cdot\vec{b}=1 and b⃗⋅c⃗=−3\vec{b}\cdot\vec{c}=-3, then 13((a⃗×b⃗)⋅c⃗)\frac{1}{3}\left((\vec{a}\times\vec{b})\cdot\vec{c}\right) is equal to __________.

Official answer

2

NTA final key.