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JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 17 March 2021, Shift 1, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

The mole fraction of a solute in a 100 molal aqueous solution is __________ ×10−2\times 10^{-2}. (Round off to the Nearest Integer). [Given : Atomic masses : H : 1.0 u, O : 16.0 u]

Official answer

64

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