Learn

Saturday, 31 October

JEE Main 2021 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 16 March 2021, Shift 2, Maths Q88

Question 88 of 90 in this shift, Maths question 28 of 30, Section B.

Let A=[a1a2]A=\begin{bmatrix}a_1\\a_2\end{bmatrix} and B=[b1b2]B=\begin{bmatrix}b_1\\b_2\end{bmatrix} be two 2×12\times1 matrices with real entries such that A=XBA=XB, where X=13[1−11k]X=\frac{1}{\sqrt3}\begin{bmatrix}1&-1\\1&k\end{bmatrix}, and k∈Rk\in\mathbf R. If a12+a22=23(b12+b22)a_1^2+a_2^2=\frac23(b_1^2+b_2^2) and (k2+1) b22≠−2b1b2(k^2+1)\,b_2^2\neq-2b_1b_2, then the value of k is ________.

Official answer

1

NTA final key.

Chapter
Matrices