JEE Main 2021 (25 Jul, Shift 2) Physics Q5: Two vectors…

Question

Two vectors $\vec{X}$ and $\vec{Y}$ have equal magnitude. The magnitude of $(\vec{X} - \vec{Y})$ is n times the magnitude of $(\vec{X} + \vec{Y})$. The angle between $\vec{X}$ and $\vec{Y}$ is :

Accepted Answer

Option 1: $\cos^{-1}\left(\frac{n^2-1}{-n^2-1}\right)$

Answer

$\cos^{-1}\left(\frac{n^2-1}{-n^2-1}\right)$

Answer

$\cos^{-1}\left(\frac{-n^2-1}{n^2-1}\right)$

Answer

$\cos^{-1}\left(\frac{n^2+1}{-n^2-1}\right)$

Answer

$\cos^{-1}\left(\frac{n^2+1}{n^2-1}\right)$

JEE Main 25 July 2021, Shift 2, Physics Q5