JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 25 July 2021, Shift 2, Physics Q23

Question 23 of 90 in this shift, Physics question 23 of 30, Section B.

A system consists of two types of gas molecules A and B having same number density

2\times10^{25}

^3

. The diameter of A and B are 10 Å and 5 Å respectively. They suffer collision at room temperature. The ratio of average distance covered by the molecule A to that of B between two successive collision is __________

\times10^{-2}

Official answer

NTA final key.

Chapter: Kinetic Theory
Topic: Kinetic Theory of Gases
Idea tested: Mean Free Path

Same idea in other shifts

Asked 6× in all

5 Apr 2024, Shift 2 · Q39If n is the number density and d is the diameter of the molecule, then the average distance covered by a molecule between two successive…EasySingle correct
8 Apr 2024, Shift 2 · Q39Given below are two statements : Statement (I) : The mean free path of gas molecules is inversely proportional to square of molecular…EasyTwo statements
27 Jun 2022, Shift 2 · Q38According to kinetic theory of gases, A. The motion of the gas molecules freezes at 0°C. B. The mean free path of gas molecules decreases…MediumOther
16 Mar 2021, Shift 2 · Q7Calculate the value of mean free path ( $\lambda$ ) for oxygen molecules at temperature $27^\circ\mathrm{C}$ and pressure $1.01\times10^5$ …EasySingle correct
2 Sep 2020, Shift 2 · Q9An ideal gas in a closed container is slowly heated. As its temperature increases, which of the following statements are true ? (A) the…MediumOther

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.