JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumCalculation
JEE Main 25 July 2021, Shift 2, Physics Q20
Question 20 of 90 in this shift, Physics question 20 of 30, Section A.
In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells, is :
The figure, in words
Potentiometer circuit: wire AB with jockey/contact C on it; the top branch has a key K, a cell marked V and a rheostat connected between A and B. Galvanometer G connects from C down to the common junction between two cells and (in series along the bottom); the end A is connected by a wire to terminal (1) (the free end of the side) and terminal (2) is the free end of the side.- (1)
- (2)Official answer
- (3)
- (4)
Official answer
Option 2
NTA final key.
- Chapter
- Current Electricity
- Topic
- Potentiometer
- Idea tested
- Comparing EMF of Two Cells