Learn

Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 22 July 2021, Shift 2, Physics Q30

Question 30 of 90 in this shift, Physics question 30 of 30, Section B.

Three students S1S_1, S2S_2 and S3S_3 perform an experiment for determining the acceleration due to gravity (g) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table. Student No. | Length of Pendulum (cm) | No. of oscillations (n) | Total time for n oscillations | Time period (s) 1 | 64.0 | 8 | 128.0 | 16.0 2 | 64.0 | 4 | 64.0 | 16.0 3 | 20.0 | 4 | 36.0 | 9.0 (Least count of length = 0.1 cm least count for time = 0.1 s) If E1E_1, E2E_2 and E3E_3 are the percentage errors in ‘g’ for students 1, 2 and 3 respectively, then the minimum percentage error is obtained by student no. ________.

The figure, in words

Table of observations (Student No., Length of Pendulum (cm), No. of oscillations (n), Total time for n oscillations, Time period (s)) as transcribed in the stem.

Official answer

1

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.