JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 26 February 2021, Shift 2, Physics Q29

Question 29 of 90 in this shift, Physics question 29 of 30, Section B.

A particle executes S.H.M. with amplitude ‘a’ and time period ‘T’. The displacement of the particle when its speed is half of maximum speed is

\frac{\sqrt{x}\,a}{2}

. The value of

x

is ________.

Official answer

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Velocity and Accel vs Position

Same idea in other shifts

Asked 6× in all

4 Apr 2026, Shift 1 · Q48The velocity of a particle executing simple harmonic motion along $x$ -axis is described as $v^2=50-x^2$ , where $x$ represents…EasyNumerical value
9 Apr 2024, Shift 1 · Q54The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes of $4$ m,…MediumNumerical value
31 Jan 2024, Shift 1 · Q54A particle performs simple harmonic motion with amplitude $A$ . Its speed is increased to three times at an instant when its displacement…MediumNumerical value
30 Jul 2022, Shift 2 · Q26A particle executing SHM has its velocity 20 cm s $^{-1}$ at mean position and acceleration of 25 cm s $^{-2}$ at one of its extreme…MediumNumerical value
24 Jun 2022, Shift 2 · Q36Two massless springs with spring constants 2 k and 9 k, carry 50 g and 100 g masses at their free ends. These two masses oscillate…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.