JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumDiagram reading
JEE Main 25 February 2021, Shift 2, Chemistry Q49
Question 49 of 90 in this shift, Chemistry question 19 of 30, Section A.
Which of the following is correct structure of -anomer of maltose ?
The figure, in words
Four Haworth-type drawings, each of two six-membered rings (ring O) joined by an O bridge, with substituent labels as listed in the option text (printed labels only; positions approximate).- (1)[figure: two six-membered rings (ring O at top) joined by an O bridge between the right ring-carbon of the left ring (H above) and the left ring-carbon of the right ring (H above). Left ring: H top-left, CH2OH on top, inner H and H, H on right, HO bottom-left, HO bottom, OH bottom-right. Right ring: H top-left, CH2OH on top, inner H and H, H right, H top-right, OH lower-right, HO bottom, OH bottom-right]
- (2)[figure: two six-membered rings (ring O at top) joined by an O bridge. Left ring: H top-left, CH2OH on top, inner H and OH, H on right, HO left, H bottom, OH bottom-right, H above the right carbon. Right ring: H top-left, CH2OH on top, inner H and OH, H, OH top-right, H lower-right, H bottom, OH bottom-right]
- (3)[figure: two six-membered rings (ring O at top) joined by an O bridge. Left ring: H top-left, CH2OH on top, inner H and OH, H on right, HO left, H bottom, OH bottom-right, H above the right carbon. Right ring: H top-left, CH2OH on top, inner H and OH, H, H top-right, OH lower-right, H bottom, OH bottom-right]Official answer
- (4)[figure: two six-membered rings (ring O at top) joined by an O bridge. Left ring: H top-left, CH2OH on top, inner H and H, H on right, HO left, OH bottom-left, OH bottom-right. Right ring: H top-left, CH2OH on top, inner H and H, H, OH top-right, H lower-right, HO bottom, OH bottom-right]
Official answer
Option 3
NTA final key.
- Chapter
- Biomolecules
- Topic
- Carbohydrates
- Idea tested
- Maltose Structure and Linkage