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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 25 February 2021, Shift 2, Physics Q22

Question 22 of 90 in this shift, Physics question 22 of 30, Section B.

The initial velocity viv_i required to project a body vertically upward from the surface of the earth to reach a height of 10R, where R is the radius of the earth, may be described in terms of escape velocity vev_e such that vi=xy×vev_i = \sqrt{\frac{x}{y}} \times v_e. The value of xx will be ____________ .

Official answer

10

NTA final key.

Chapter
Gravitation
Topic
Gravitational Potential
Idea tested
Maximum Height Using Exact Potential

Same idea in other shifts

Asked 2× in all
  1. 26 Jul 2022, Shift 2 · Q38A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.