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Saturday, 31 October

JEE Main 2021 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 24 February 2021, Shift 2, Maths Q87

Question 87 of 90 in this shift, Maths question 27 of 30, Section B.

If a+α=1a+\alpha=1, b+β=2b+\beta=2 and af(x)+αf(1x)=bx+βxaf(x)+\alpha f\left(\frac{1}{x}\right)=bx+\frac{\beta}{x}, x≠0x\neq0, then the value of the expression f(x)+f(1x)x+1x\frac{f(x)+f\left(\frac{1}{x}\right)}{x+\frac{1}{x}} is __________.

Official answer

2

NTA final key.

Chapter
Relations and Functions
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.