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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumApplication

JEE Main 24 February 2021, Shift 1, Chemistry Q47

Question 47 of 90 in this shift, Chemistry question 17 of 30, Section A.

‘A’ and ‘B’ in the following reactions are : [figure] →KCNNaNO2/HCl\xrightarrow[\mathrm{KCN}]{\mathrm{NaNO_2/HCl}} (A) →SnCl2/HCl/H3O+\xrightarrow{\mathrm{SnCl_2/HCl/H_3O^+}} (B)

The figure, in words

Stem structure: benzene ring bearing NH2; first arrow labelled NaNO2/HCl (above) and KCN (below) to (A); second arrow labelled SnCl2/HCl/H3O+ to (B).
  1. (1)(A) : [figure: benzene ring bearing N2+Cl− (+ above N, − above Cl)] (B) : [figure: benzene ring bearing Cl]
  2. (2)(A) : [figure: benzene ring bearing N2+Cl− (+ above N, − above Cl)] (B) : [figure: benzene ring bearing CHO]
  3. (3)(A) : [figure: benzene ring bearing CN] (B) : [figure: benzene ring bearing Cl]
  4. (4)(A) : [figure: benzene ring bearing CN] (B) : [figure: benzene ring bearing CHO]Official answer

Official answer

Option 4

NTA final key.

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