JEE Main 2021 (24 Feb, Shift 1) Chemistry Q45: Hydrocarbons

Question

Identify products A and B.
[figure] $\xrightarrow[273\ \mathrm{K}]{\mathrm{dil.\ KMnO_4}} \mathrm{A} \xrightarrow{\mathrm{CrO_3}} \mathrm{B}$

Accepted Answer

Option 2: A: [figure: five-membered ring with one ring carbon bearing CH3 and OH, and the adjacent ring carbon bearing OH]  B: [figure: five-membered ring with one ring carbon bearing CH3 and OH, and the adjacent ring carbon drawn as C=O]

Answer

A: [figure: five-membered ring with one ring carbon bearing CH3 and OH, and the adjacent ring carbon bearing OH]  B: [figure: five-membered ring with CH3 on one ring carbon; a ring double bond between that carbon and its upper ring neighbour, and its other ring neighbour (below) drawn as C=O]

Answer

A: [figure: five-membered ring with one ring carbon bearing CH3 and OH, and the adjacent ring carbon bearing OH]  B: [figure: five-membered ring with one ring carbon bearing CH3 and OH, and the adjacent ring carbon drawn as C=O]

Answer

A: [figure: five-membered ring with one ring carbon bearing CH3 and the adjacent ring carbon bearing OH]  B: [figure: five-membered ring with one ring carbon bearing CH3 and the adjacent ring carbon drawn as C=O]

Answer

A : $\mathrm{OHC{-}CH_2CH_2CH_2{-}C(=O){-}CH_3}$  B : $\mathrm{HOOC{-}CH_2CH_2CH_2{-}C(=O){-}CH_3}$ [figure: C=O drawn above the carbon bonded to CH3 in each]

JEE Main 24 February 2021, Shift 1, Chemistry Q45

Same idea in other shifts