JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumConceptual

JEE Main 24 February 2021, Shift 1, Physics Q4

Question 4 of 90 in this shift, Physics question 4 of 30, Section A.

Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as ;

I_1

= M.I. of thin circular ring about its diameter,

I_2

= M.I. of circular disc about an axis perpendicular to disc and going through the centre,

I_3

= M.I. of solid cylinder about its axis and

I_4

= M.I. of solid sphere about its diameter. Then :

(1) $I_1+I_2=I_3+\frac{5}{2}\,I_4$
(2) $I_1+I_3<I_2+I_4$
(3) $I_1=I_2=I_3<I_4$
(4) $I_1=I_2=I_3>I_4$ Official answer

Official answer

Option 4

NTA final key.

Chapter: System of Particles and Rotational Motion
Topic: Moment of Inertia
Idea tested: Comparing MOI of Standard Shapes

Same topic in other shifts

All Moment of Inertia questions

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.