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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceSingle correctEasyConceptual

JEE Main 24 February 2021, Shift 1, Chemistry Q36

Question 36 of 90 in this shift, Chemistry question 6 of 30, Section A.

Al2O3\mathrm{Al_2O_3} was leached with alkali to get X. The solution of X on passing of gas Y, forms Z. X, Y and Z respectively are :
  1. (1)X=Na[Al(OH)4], Y=SO2, Z=Al2O3X=\mathrm{Na[Al(OH)_4]},\ Y=\mathrm{SO_2},\ Z=\mathrm{Al_2O_3}
  2. (2)X=Al(OH)3, Y=SO2, Z=Al2O3.xH2OX=\mathrm{Al(OH)_3},\ Y=\mathrm{SO_2},\ Z=\mathrm{Al_2O_3.}x\mathrm{H_2O}
  3. (3)X=Al(OH)3, Y=CO2, Z=Al2O3X=\mathrm{Al(OH)_3},\ Y=\mathrm{CO_2},\ Z=\mathrm{Al_2O_3}
  4. (4)X=Na[Al(OH)4], Y=CO2, Z=Al2O3.xH2OX=\mathrm{Na[Al(OH)_4]},\ Y=\mathrm{CO_2},\ Z=\mathrm{Al_2O_3.}x\mathrm{H_2O}Official answer

Official answer

Option 4

NTA final key.