JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 24 February 2021, Shift 1, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

A resonance circuit having inductance and resistance

2\times10^{-4}

H and 6.28

\Omega

respectively oscillates at 10 MHz frequency. The value of quality factor of this resonator is __________. [

\pi=3.14

]

Official answer

2000

NTA final key.

Chapter: Alternating Current
Topic: LCR Resonance
Idea tested: Quality Factor Definition

Same topic in other shifts

All LCR Resonance questions

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6 Apr 2024, Shift 1 · Q44Given below are two statements : Statement I : In an LCR series circuit, current is maximum at resonance. Statement II : Current in a…EasyTwo statements
6 Apr 2024, Shift 2 · Q59For a given series LCR circuit it is found that maximum current is drawn when value of variable capacitance is 2.5 nF. If resistance of…EasyNumerical value
8 Apr 2024, Shift 1 · Q50A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other…EasySingle correct
1 Feb 2024, Shift 1 · Q43In series LCR circuit, the capacitance is changed from C to 4C. To keep the resonance frequency unchanged, the new inductance should be :EasySingle correct
29 Jan 2024, Shift 1 · Q43A capacitor of capacitance $100\ \mu$ F is charged to a potential of 12 V and connected to a 6.4 mH inductor to produce oscillations. The…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.