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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 24 February 2021, Shift 1, Physics Q12

Question 12 of 90 in this shift, Physics question 12 of 30, Section A.

A cell E1E_1 of emf 6 V and internal resistance 2 Ω\Omega is connected with another cell E2E_2 of emf 4 V and internal resistance 8 Ω\Omega (as shown in the figure). The potential difference across points X and Y is :

The figure, in words

Circuit: points P, X, Y on the top wire; cell E1 (labelled 6 V, 2 Ω) between P and X, cell E2 (labelled 4 V, 8 Ω) between X and Y; the wire from P and from Y are joined through a rectangular loop along the bottom (closed circuit with no other elements).
  1. (1)2.02.0 V
  2. (2)3.63.6 V
  3. (3)5.65.6 VOfficial answer
  4. (4)10.010.0 V

Official answer

Option 3

NTA final key.

Chapter
Current Electricity
Topic
Kirchhoff's Laws
Idea tested
Reversed Cells in Series

Same idea in other shifts

Asked 2× in all
  1. 30 Jan 2024, Shift 1 · Q56Two cells are connected in opposition as shown. Cell E1E_1 is of 8 V emf and 2 Ω2\ \Omega internal resistance; the cell E2E_2 is of 2 V emf…EasyNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.