JEE Main 2021 (31 Aug, Shift 2) Maths Q66: An angle of…

Question

An angle of intersection of the curves, $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{b}^2} = 1$ and $x^2+y^2 = \mathrm{ab}$, $\mathrm{a} > \mathrm{b}$, is :

Accepted Answer

Option 1: $	an^{-1}\left(\frac{\mathrm{a-b}}{\sqrt{\mathrm{ab}}}ight)$

Answer

$	an^{-1}\left(\frac{\mathrm{a-b}}{\sqrt{\mathrm{ab}}}ight)$

Answer

$	an^{-1}\left(\frac{\mathrm{a+b}}{\sqrt{\mathrm{ab}}}ight)$

Answer

$	an^{-1}\left(\frac{\mathrm{a-b}}{2\sqrt{\mathrm{ab}}}ight)$

Answer

$	an^{-1}\left(2\sqrt{\mathrm{ab}}ight)$

JEE Main 31 August 2021, Shift 2, Maths Q66

Same idea in other shifts