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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumApplication

JEE Main 31 August 2021, Shift 2, Chemistry Q45

Question 45 of 90 in this shift, Chemistry question 15 of 30, Section A.

The structures of A and B formed in the following reaction are : [Ph = −C6H5-\mathrm{C_6H_5}] [benzene ring (with inner circle) + a five-membered cyclic anhydride drawn as a ring containing O with two C=O groups] -> (AlCl3_3(2 eq)) A -> (Zn/Hg, HCl) B

The figure, in words

Benzene ring plus a cyclic five-membered anhydride (ring O with two C=O) with AlCl3 (2 eq) over arrow to A, then Zn/Hg over HCl to B. Options are line-drawn structures of A and B.
  1. (1)A = Ph-C(=O)-CH2-CH2-C(=O)-OH (line drawing: Ph attached to C=O, then two CH2, then COOH), B = Ph-CH2-CH2-CH2-C(=O)-OH (line drawing)Official answer
  2. (2)A = Ph-C(=O)-CH2-CH2-C(=O)-OH (line drawing), B = Ph-CH2-CH2-CH2-CH2-OH (line drawing, chain ending in OH)
  3. (3)A = Ph-C(=O)-CH2-CH3 (line drawing), B = Ph-CH(OH)-CH2-CH3 (line drawing)
  4. (4)A = Ph-C(=O)-CH2-CH3 (line drawing), B = Ph-CH2-CH2-CH3 (line drawing)

Official answer

Option 1

NTA final key.