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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 31 August 2021, Shift 2, Physics Q10

Question 10 of 90 in this shift, Physics question 10 of 30, Section A.

A bob of mass 'm' suspended by a thread of length ll undergoes simple harmonic oscillations with time period T. If the bob is immersed in a liquid that has density 14\frac{1}{4} times that of the bob and the length of the thread is increased by 1/3rd1/3^{\mathrm{rd}} of the original length, then the time period of the simple harmonic oscillations will be :
  1. (1)43\frac{4}{3} TOfficial answer
  2. (2)34\frac{3}{4} T
  3. (3)32\frac{3}{2} T
  4. (4)T

Official answer

Option 1

NTA final key.

Chapter
Oscillations
Topic
Pendulums
Idea tested
Pendulum in Fluids

Same idea in other shifts

Asked 2× in all
  1. 29 Jul 2022, Shift 2 · Q57The metallic bob of simple pendulum has the relative density 5. The time period of this pendulum is 10 s. If the metallic bob is immersed…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.