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Saturday, 31 October

JEE Main 2021 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 27 August 2021, Shift 2, Maths Q84

Question 84 of 90 in this shift, Maths question 24 of 30, Section B.

If ∫2ex+3e−x4ex+7e−x dx=114(ux+vlog⁡e(4ex+7e−x))+C\int \frac{2e^x + 3e^{-x}}{4e^x + 7e^{-x}}\, dx = \frac{1}{14}\left(ux + v \log_e(4e^x + 7e^{-x})\right) + C, where C is a constant of integration, then u+vu + v is equal to __________.

Official answer

7

NTA final key.

Chapter
Integrals