JEE Main 2021 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 27 August 2021, Shift 2, Maths Q73

Question 73 of 90 in this shift, Maths question 13 of 30, Section A.

If the solution curve of the differential equation

(2x - 10y^3)dy + y\,dx = 0

, passes through the points

(0, 1)

and

(2, \beta)

, then

\beta

is a root of the equation :

(1) $2y^5 - 2y - 1 = 0$
(2) $2y^5 - y^2 - 2 = 0$
(3) $y^5 - y^2 - 1 = 0$ Official answer
(4) $y^5 - 2y - 2 = 0$

Official answer

Option 3

NTA final key.

Chapter: Differential Equations
Topic: Linear Differential Equations
Idea tested: Linear in x Form

Same idea in other shifts

Asked 6× in all

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24 Jun 2022, Shift 1 · Q14If $x=x(y)$ is the solution of the differential equation $y\frac{dx}{dy}=2x+y^3(y+1)e^y,\ x(1)=0$ ; then $x(e)$ is equal to :MediumSingle correct
3 Aug 2021, Shift 2 · Q87If the solution $y = y(x)$ of the differential equation $\left(y + 3x^4\right)\frac{dx}{dy} = x,\ x > 0$ , satisfies $y(1) = -1$ , then the…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.