JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 27 August 2021, Shift 2, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is

x \times 10^{-2}

. The value of

x

is __________. (Nearest integer) [Atomic weight : H = 1.008; C = 12.00; O = 16.00]

Official answer

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Stoichiometry
Idea tested: Limiting Reagent Identification

Same idea in other shifts

Asked 8× in all

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30 Jun 2022, Shift 1 · Q81Blister copper is produced by reaction of copper oxide with copper sulphide.…MediumNumerical value
16 Mar 2021, Shift 2 · Q51When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, ________ $\times10^{-5}$ moles of lead…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.