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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumDiagram reading

JEE Main 27 August 2021, Shift 2, Chemistry Q43

Question 43 of 90 in this shift, Chemistry question 13 of 30, Section A.

The major product (A) formed in the reaction given below is : [reaction drawn: CH3−CH2−CH−CH2−Br\mathrm{CH_3-CH_2-CH-CH_2-Br} with the CH carbon bonded to a benzene ring below it, + CH3O\mathrm{CH_3O} with a circled minus charge, arrow labelled CH3OH\mathrm{CH_3OH}, giving A (Major Product)]

The figure, in words

Stem: CH3-CH2-CH(C6 ring drawn below)-CH2-Br plus CH3O(-) in CH3OH. Options are printed condensed structures with a drawn benzene ring below the CH (or C) carbon.
  1. (1)[structure: CH3−CH2−CH−CH2−OCH3\mathrm{CH_3-CH_2-CH-CH_2-OCH_3} with the CH carbon bonded to a benzene ring below it]
  2. (2)[structure: CH3−CH2−C=CH2\mathrm{CH_3-CH_2-C=CH_2} with the C bonded to a benzene ring below it]Official answer
  3. (3)[structure: CH3−CH2−CH−CH2Br\mathrm{CH_3-CH_2-CH-CH_2Br} with the CH carbon bonded to a benzene ring below it; the ring has OCH3\mathrm{OCH_3} at the bottom (para to the chain)]
  4. (4)[structure: CH3−CH2−CH−CH2−OH\mathrm{CH_3-CH_2-CH-CH_2-OH} with the CH carbon bonded to a benzene ring below it]

Official answer

Option 2

NTA final key.

Chapter
Haloalkanes and Haloarenes
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.