Learn

Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 26 August 2021, Shift 2, Maths Q72

Question 72 of 90 in this shift, Maths question 12 of 30, Section A.

The point P(−26,3)\mathrm{P}(-2\sqrt{6},\sqrt{3}) lies on the hyperbola x2a2−y2b2=1\frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{b}^2}=1 having eccentricity 52\frac{\sqrt{5}}{2}. If the tangent and normal at P to the hyperbola intersect its conjugate axis at the points Q and R respectively, then QR is equal to :
  1. (1)434\sqrt{3}
  2. (2)363\sqrt{6}
  3. (3)66
  4. (4)636\sqrt{3}Official answer

Official answer

Option 4

NTA final key.