JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 26 August 2021, Shift 2, Chemistry Q56

Question 56 of 90 in this shift, Chemistry question 26 of 30, Section B.

For the galvanic cell,

\mathrm{Zn(s) + Cu^{2+}}

(0.02 M)

\rightarrow \mathrm{Zn^{2+}}

(0.04 M)

+ \mathrm{Cu(s)}

\mathrm{E_{cell}}

= __________

\times 10^{-2}

V. (Nearest integer) [Use :

\mathrm{E^0_{Cu/Cu^{2+}}}

-0.34

\mathrm{E^0_{Zn/Zn^{2+}}}

+0.76

\frac{2.303\ RT}{F}

= 0.059V ]

Official answer

109

NTA final key.

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Full Cell Nernst Equation

Same idea in other shifts

Asked 12× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.